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	<title>Comments on: Puzzle #8 &#8211; Clock Frequency Driver</title>
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	<link>http://asicdigitaldesign.wordpress.com/2007/08/13/puzzle-8-clock-frequency-driver/</link>
	<description>Tricks and Tips for ASIC Digital Designers</description>
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		<title>By: ankit</title>
		<link>http://asicdigitaldesign.wordpress.com/2007/08/13/puzzle-8-clock-frequency-driver/#comment-1721</link>
		<dc:creator>ankit</dc:creator>
		<pubDate>Thu, 14 Aug 2008 17:27:35 +0000</pubDate>
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		<description>if we have symetric nand gate than I think we only need to covert ex-or gate to nand gate

and inverter to nand gate also 

p&#039;=(p nand p)

n&#039;=(n nand n)

i1=(p&#039; nand n)

i2=(p nand n&#039;)

output=(i1 nand i2)

here i1 and i2 are internal stages</description>
		<content:encoded><![CDATA[<p>if we have symetric nand gate than I think we only need to covert ex-or gate to nand gate</p>
<p>and inverter to nand gate also </p>
<p>p&#8217;=(p nand p)</p>
<p>n&#8217;=(n nand n)</p>
<p>i1=(p&#8217; nand n)</p>
<p>i2=(p nand n&#8217;)</p>
<p>output=(i1 nand i2)</p>
<p>here i1 and i2 are internal stages</p>
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		<title>By: Puzzle #8 - Clock Frequency Driver - Solution &#171; Adventures in ASIC Digital Design</title>
		<link>http://asicdigitaldesign.wordpress.com/2007/08/13/puzzle-8-clock-frequency-driver/#comment-1518</link>
		<dc:creator>Puzzle #8 - Clock Frequency Driver - Solution &#171; Adventures in ASIC Digital Design</dc:creator>
		<pubDate>Wed, 26 Mar 2008 16:27:05 +0000</pubDate>
		<guid isPermaLink="false">http://asicdigitaldesign.wordpress.com/2007/08/13/puzzle-8-clock-frequency-driver/#comment-1518</guid>
		<description>[...] The clock frequency driver puzzle drew little attention compared to the others and I got only one complete and correct solution for it. What follows is my own solution which I hope will be easily understood. [...]</description>
		<content:encoded><![CDATA[<p>[...] The clock frequency driver puzzle drew little attention compared to the others and I got only one complete and correct solution for it. What follows is my own solution which I hope will be easily understood. [...]</p>
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	<item>
		<title>By: Zhi</title>
		<link>http://asicdigitaldesign.wordpress.com/2007/08/13/puzzle-8-clock-frequency-driver/#comment-1219</link>
		<dc:creator>Zhi</dc:creator>
		<pubDate>Mon, 26 Nov 2007 02:40:04 +0000</pubDate>
		<guid isPermaLink="false">http://asicdigitaldesign.wordpress.com/2007/08/13/puzzle-8-clock-frequency-driver/#comment-1219</guid>
		<description>let&#039;s think A is a symmetrical cell too
A= (P NAND N) 
B=(~P NAND ~N)
above two items can be implemented by nand gate and inverter,
then (A NAND B) , add a inverter at last, it&#039;s OK.
I cannot give a schematic because of no drawing tool, if it&#039;s wrong,pls tell me why. thanks.</description>
		<content:encoded><![CDATA[<p>let&#8217;s think A is a symmetrical cell too<br />
A= (P NAND N)<br />
B=(~P NAND ~N)<br />
above two items can be implemented by nand gate and inverter,<br />
then (A NAND B) , add a inverter at last, it&#8217;s OK.<br />
I cannot give a schematic because of no drawing tool, if it&#8217;s wrong,pls tell me why. thanks.</p>
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